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Phoenix [80]
3 years ago
7

Find the 2nd and 3rd term of the sequence 1, ___, ___, –11, –15, ...

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

-3, -7

Step-by-step explanation:

It's an arithmetic sequence subtracting four each time

-3, -7

Elena L [17]3 years ago
5 0

Answer:

Step-by-step explanation:

-4 and - 7 are the second and third term

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levacccp [35]

Answer:

\frac{1}{4} (x-5)=13

Step-by-step explanation:

So when we multiply this is what we get:

\frac{x-5}{4}=13

then we multiply the 4 by 13:

x-5=52

then after that we add 52+5 and we get:

x=57\\

4 0
2 years ago
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Solve 9x^2- 17x- 85 = 0 Give your solutions correct to 3 significant figures.​
dybincka [34]

Answer:

x =\frac{17}{18} +\frac{1}{18} \sqrt{3349} OR x =\frac{17}{18} +\frac{-1}{18} \sqrt{3349}

Step-by-step explanation:

9x2−17x−85=0

For this equation: a=9, b=-17, c=-85

9x2+−17x+−85=0

Step 1: Use quadratic formula with a=9, b=-17, c=-85.

x =\frac{-b + \sqrt{b^{2}-4ac } }{2a}

x  =\frac{-(-17)+\sqrt{(-17)^{2} -4(9)(-85)} }{2(9)}

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4 0
2 years ago
100/32 can someone help me how much would this be in fraction
kap26 [50]
Your answer would be 3 and 1/8
7 0
2 years ago
If a number line shows tick marks that are not labeled, can you determine the coordinate of a point located at an unlabeled tick
GarryVolchara [31]

If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.

For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.

Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.

3 0
3 years ago
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daser333 [38]

Answer:

-90=x(x-18)

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you need to use quadratic formula and you will find square root a negative ( -9 ), which is an imaginary no.

square root (-9) = 3i

4 0
2 years ago
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