Oop- I’ll pass on telling you everything about me :/
Answer:

option B is correct
Step-by-step explanation:
We have 5 spaces in the license plate:
_ _ _ _ _
we have 26 available letters, and 10 available numbers.
starting with letters:
- how many choices do i have to place the 1st letter? 26.
26 _ _ _ _
- how many choices do i have to place the 2nd letter? 26 (since we're allowed to repeat letters)
26 26 _ _ _
- how many choices do i have to place the 3rd letter? 26
26 26 26 _ _
we've used all the places for letters, (note: the exact position of the letters doesn't matter here, the first letter could've been placed anywhere in _ _ _ _ _, but the amount of possible choices for letters would always be 26).
let's move on to numbers.
- how many choices do i have to place the 1st number? 10
26 26 26 10 _
- how many choices do i have to place the 2nd number? 10
26 26 26 10 10
we've completed our number plate. Next we'll simply multiply all these numbers to get all the possible arrangements in which numbers and letters can be displayed on a license place.

option B is correct
Bicycle has 2 wheels and 2 pedals
tricycle has 3 wheels and 2 pedals
EQ 1 : 2b + 2t = 170 pedals
EQ 2: 2b +3t = 206 wheels
subtract EQ 1 from EQ 2
2b +3t = 206 - 2b + 2t = 170 = t=36
there were 36 tricycles
36 x 2 = 72 pedals
170 pedals - 72 = 98 pedals left
98/2 = 49 bicycles
36 Tricycles and 49 bicycles
Answer:
w=9
Step-by-step explanation:
Our equation is: 8w-15=57
Add 15 to both sides
-15 is now gone because we added 15 so it would be zero
and we have 72 because 15 plus 57 is 72
Now we have:
8w=72
Divide by 8 on both sides
8w cancels out to just w
and 72 divided by 8 is 9
And you're left with:
w=9