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pickupchik [31]
2 years ago
5

Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form. (2 points)

Mathematics
1 answer:
kykrilka [37]2 years ago
5 0
The answer is: y-3= 2 (x-1)
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Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound
Simora [160]

Answer:

t=2.5\ years  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045  

substitute in the formula above   and solve for t

14,000=12,500(e)^{0.045t}  

Simplify

14,000/12,500=(e)^{0.045t}  

1.12=(e)^{0.045t}  

Apply ln both sides

ln(1.12)=ln[(e)^{0.045t}]  

ln(1.12)=(0.045t)ln(e)  

Remember that

ln(e)=1  

so

ln(1.12)=(0.045t)  

t=ln(1.12)/(0.045)  

t=2.5\ years  

3 0
3 years ago
Given that cos (x) = 1/3, find sin (90 - x)
drek231 [11]
\sin{(A - B)} \equiv \sin{A}\cos{B} - \cos{A}\sin{B} \\\\
\therefore \sin{(90 - x)}\\
 = \sin{(90)}\cos{(x)} - \cos{(90)}\sin{(x)} \\
= (1)\cos{(x)} - (0)\sin{(x)} \\
= \cos{x} - 0 \\
= \cos{x} \\
= \frac{1}{3}

3 0
3 years ago
Read 2 more answers
The monthly budget for the front of the house is $9,000. You spent 6% of the budget on fresh flowers. How much did you spend on
adelina 88 [10]

Answer:

$540

Step-by-step explanation:

Since we are paying 6% of the money on flowers we need to multiply our budget by .06. Let x equal the amount of money we payed for flowers.

x=9000*.06

Multiple the two numbers

x=540

We payed $540 for the flowers

8 0
2 years ago
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What is the approximate difference in average daily miles between the two weeks?
Ray Of Light [21]
24 would be the answer
5 0
2 years ago
Apply the​ 68-95-99.7 rule to answer the question. The lifetimes of light bulbs of a particular type are normally distributed wi
Montano1993 [528]

Answer:

95%.

Step-by-step explanation:

We have been given that the lifetimes of light bulbs of a particular type are normally distributed with a mean of 370 hours and a standard deviation of 7 hours.

We are asked to find the percentage of the bulbs whose lifetimes lie within 2 standard deviations to either side of the​ mean using empirical rule.

The empirical rule (68-95-99.7) states that approximately 68% of data points lie within 1 standard deviation of mean and 95% of data points lie within two standard deviation of mean. 99.7% of data points lie within three standard deviation of mean.

Therefore, approximately 95% of data points lie within two standard deviation of mean.

7 0
3 years ago
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