Answer:
Yes, there is enough evidence to say the proportions are the same.
Step-by-step explanation:
Null hypothesis: The proportions are the same.
Alternate hypothesis: The proportions are not the same.
Data given:
p1 = 51% = 0.51
n1 = 200
p2 = 48% = 0.48
n2 = 150
pooled proportion (p) = (n1p1 + n2p2) ÷ (n1 + n2) = (200×0.51 + 150×0.48) ÷ (200 + 150) = 174 ÷ 350 = 0.497
Test statistic (z) = (p1 - p2) ÷ sqrt[p(1-p)(1/n1 + 1/n2) = (0.51 - 0.48) ÷ sqrt[0.497(1-0.497)(1/200 + 1/150)] = 0.03 ÷ 0.054 = 0.556
The test is a two-tailed test. At 0.10 significance level the critical values -1.645 and 1.645
Conclusion:
Fail to reject the null hypothesis because the test statistic 0.556 falls within the region bounded by the critical values.
Answer:
(B) 20
Step-by-step explanation:
Let small puppet be represented by-----------------s
Let large puppet be represented by-----------------l
Total number of puppets expression will be: s+l =25---------a
The expression for total costs will be : 1$ s + $2l=$30-------b
Equation a can be written as; s= 25-l ------------c
Use equation c in equation b as
$1( 25-l )+$ 2l = $30
25-l + 2l = 30
25+l =30
l= 30-25 =5
l, large puppets = 5
s, small puppets = 25-5 = 20
Answer choice A is incorrect because 25 is the total number of all puppets
Answer choice C and D are incorrect because the numbers are less that that of small puppets.
The answer to this is <span>4 and 9 over 16.</span>
Circles will never have a side but they only have 1 line that can be counted as a side.
Answer:
e. 0.0072
Step-by-step explanation:
We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .
Let Z = 
~ N(0,1) where, Xbar = mean contents of six randomly
selected bottles
n = sample size i.e. 6
So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)
P(Xbar < 295) = P( < 
) = P(Z < -2.45) = P(Z > 2.45)
Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .
Therefore, option e is correct .
