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3 years ago

At which value(s) is the expression

Mathematics

1 answer:

ratelena [41]3 years ago

4 0

Idk check out wyzant.com or cymath.com

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Enter numbers in the boxes to write an equation that is equivalent to 3/4b−2/3b=−9

Nana76 [90]

Answer:

3/4b−2/3b=−9 = -108. so, i just used equivalent fractions of both of those numbers :D

Step-by-step explanation:

6/8b - 4/6b = -9

5 0

2 years ago

How would I find the Max/min of this function f(x) = 2x squared +18x +16

slamgirl [31]

F(x)=2x²+18x+16
1) we have to calculate the first derived.

f´(x)=4x+18

2) Now, we equalize the first derived to "0" and find out the value of "x"
4x+18=0
4x=-18
x=-18/4=-4.5

3)we calculate the second derived
f´´(x)=4>0 ⇒we have a minimum at x=-4.5

4) Now we calculate the value of "y".
f(-4.5)=2(-4.5)²+18(-4.5)+16=40.5-81+16=-24.5

Therefore; Exist a minimum at (-4.5 , -24.5)

7 0

3 years ago

1. Draw an appropriate Venn diagram to depict each of the following sets. U = The set of integers. A = The set of even integers.

CaHeK987 [17]

The attached diagram represents the Venn diagram of the sets

<h3>How to draw the Venn diagram?</h3>

The sets are given as:

The universal set, U = The set of integers.
A = The set of even integers.
B = The set of odd integers.
C = The set of multiples of 3.
D= The set of prime numbers

From the above representation, we have the following highlights:

Set A and set B will not intersect, because no number can be even and odd
Set C and set D will intersect set A because they have common elements 6 and 2, respectively
Set C and set D will intersect set B because they have common elements 3 and 3, respectively

Using the above highlights, we can now draw the Venn diagram

See attachment for the Venn diagram

Read more about Venn diagram at:

brainly.com/question/4910584

#SPJ1

3 0

2 years ago

Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5

MAXImum [283]

Answer:

Step-by-step explanation:

$\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7$

5 0

3 years ago

Please help meeeee

miskamm [114]

Answer:

the graph has opposite x intercepts of b and -b. the graph has y intercepts at –b². the graph of the function symmetrical about the y-axis.

Step-by-step explanation:

3 0

3 years ago