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klemol [59]
2 years ago
8

The product of a number and -5 is -115

Mathematics
1 answer:
kherson [118]2 years ago
8 0
The answer is 23, Times -5 by 23
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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

b^2 - 4ac

The solution contains the term \sqrt{b^2 - 4ac} which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation 2x^2 - 7x - 9

b^2 - 4ac

= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121

This equation has two real number solutions.

For the quadratic equation 4x^ 2 - 3x- 1

b^2 - 4ac

= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

5 0
1 year ago
1 1/8+42/3. COMMON DENOMENATOR???
bearhunter [10]

Answer:

a common denominator would be 21 bc 8 x 3 = 21

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Which statement best describes a solution to the system of equations 3x+Y=17 X+2y=49 A. It has no solution B. It has infinite so
andreev551 [17]

Answer:

  It has a single solution x=-3 y=26

Step-by-step explanation:

The ratios of coefficients of x and y are different, so the pair of equations has one solution. It is easy to tell the first offered solution (15, 17) does not satisfy the first equation, so that choice is eliminated.

Fortunately, the second offered solution, (x, y) = (-3, 26), satisfies both equations.

The equations have a single solution: (x, y) = (-3, 26).

8 0
3 years ago
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Divide 3p2 + 6p + 2 by 3p2.
kondor19780726 [428]

We need to divide

\frac{3p^2+6p+2}{3p}

So, we can divide each terms of the numerator by 3p. So,

\frac{3p^2}{3p} +\frac{6p}{3p} +\frac{2}{3p}

=p+2+\frac{2}{3p}

\frac{2}{3p} [/tex] cannot be further simplify. So, the final answer is:

p+2+\frac{2}{3p}

4 0
3 years ago
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Evaluate each expression.<br> 6! =<br> 3!. 21 =<br> 11
NNADVOKAT [17]

Answer:

here we work with factorials, so if we have a whole number N, then:

N! = N*(N-1)*.....*2*1

then, for the given expressions we have:

1) 6! = 6*5*4*3*2*1 = 720.

2) 3!*21 = (3*2*1)*21 = 216

3) and the last expression seems incomplete, i guess this is:

11! = 11*10*9*8*7*6*5*4*3*2*1 = 39,916,800

8 0
3 years ago
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