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2 years ago

What domain, range, median, and mode?

1 answer:

6 0

I don't know domain but range is the smallest number and largest number, median is the middle number when the numbers are ordered from least to greatest, and the mode is the most common or reoccuring variable in a set of numbers.

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What is the lateral surface area of a square pyramid with a side length 11.2 cm and a slant height 20 cm

madam [21]

Notice the picture below

the lateral area, or just the area of the sides, well, the sides are really just 4 triangles, so just get the area of each, and sum them up, that's the lateral area

3 0

2 years ago

Read 2 more answers

Which decimal is equivalent to 8%

Nikitich [7]

Answer:

$0.08$

Step-by-step explanation:

Given : 8%

To find the decimal value of the percentage number

Remove the percentage symbol with 100 in the denominator

gives

$\frac{8}{100}\\$

Now taking the numerator to the decimal place equal to the number of zeros in the denominator or simply divide denominator with numerator.

Gives = $0.08$

So, the decimal equivalent of the given value is $0.08$

3 0

3 years ago

Read 2 more answers

Express (16³) 1/4 in simplest radical form.

Doss [256]

Answer:

Step-by-step explanation:

4 0

1 year ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

11 months ago

Please help quickly.Thanks :)

Klio2033 [76]

Multiply 2x-5y= -21 by 3 to make it 6x-15y= -63
Multiply 3x-3y= -18 by -5 to make it -15x+15y=90

This cancels the y’s out which leaves us with

6x=-63
&
-15x=90

x for 6x=-63 equals - 10.5 so x is - 10.5 and for -15x=90, x= -6

Then you plug in x into any equation you’d like to find y.

Let’s plug in - 10.5 into 6x... equation.

6(- 10.5)-15y=-63

63-15y= -63
-63 -63

-15y=0
y=0 and x= - 10.5. When you plug in this values it makes the equation true!

But the correct answer is the first one north. Sorry if I’m doing too much hahah

If I’m confusing here’s the right answer...

6x-15y= -63
-15x+15y=90

5 0

2 years ago