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3241004551 [841]
4 years ago
13

How long would it take to earn $6,000 in interest on a principal of $9,000 at an annual simple interest rate of 4.1%? Use the si

mple interest formula I = prt, where I is the interest earned, p is the principal, r is the interest rate per year, and t is the time in years.
Mathematics
1 answer:
e-lub [12.9K]4 years ago
4 0
Ok so we are given 6000 and I think that would be I
We are also given 9000, and I think that would be p
Also we are given 4.1% or 0.041 and I think that would be r
So the formula is 
I = prt
6000 = 9000*0.041*t                        So we are trying to figure out t, time
6000/0.041 = 146341.463
<span>146341.463/9000 = 16.2601626 
I believe your answer would be</span> <span>16.2601626, please let me know if that's right because I'm really not sure.</span>
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2 years ago
Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.
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81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

  • a² - b² is a difference of two squares
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∵ The binomial is 81 a² - 25 z^{6}

∵ \sqrt{81} = 9

∵ \sqrt{a^{2} } = a

∴ \sqrt{81a^{2}}=9a

∵ \sqrt{25} = 5

∵ \sqrt{z^{6}} = z³

∴ \sqrt{25z^{6}}=5z^{3}

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∴ 81 a² - 25 z^{6}  is a difference of two squares

∵ Its factorization is two identical brackets with different

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∵ 81 a² = 9a × 9a

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- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 z^{6} = (9a + 5z³)(9a - 5z³)

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

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