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Tems11 [23]
3 years ago
8

Please answer a few questions. :)

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0
Sorry I can't read it,
 otherwise i would be happy to help you

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∠C and ​ ∠D ​ are vertical angles with m∠C=−x+26 and m∠D=2x−10 .<br><br><br><br> What is m∠D ?
grin007 [14]

Answer:

the correct answer is 14

Step-by-step explanation:

6 0
3 years ago
kamari opens a bank account with 250 five weeks her account balances 800 what was the average rate of change of her account bala
Anettt [7]
The answer is an average rate of change of 110 more dollars in her account per week. You find this by first subtracting the starting amount of 250 from the end amount of 800 that equals 550. then you divide that number by five, the number of weeks, to get the average rate of change.
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3 years ago
Please help, thank you
abruzzese [7]

Answer:

sorry but the question won't load i would love to help though

Step-by-step explanation:

4 0
2 years ago
(01.03. 106, 1.08 HC)
zlopas [31]

Answer:

  A) see attached for a graph. Range: (-∞, 7]

  B) asymptotes: x = 1, y = -2, y = -1

  C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

<h3>Part A</h3>

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

  \dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

__

<h3>Part B</h3>

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

__

<h3>Part C</h3>

The end behavior is defined by the horizontal asymptotes:

  for x → -∞, y → -2

  for x → ∞, y → -1

7 0
2 years ago
Prove that: 1=SecB.CosB​
Schach [20]

Answer:

Js

Step-by-step explanation:

U bot

I am hacker

3 0
3 years ago
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