Answer:
yes
Step-by-step explanation:
took the same quiz got it right
Area = length x width
Area = 21 square cm
Width = x
Length = 3x + 2
21 = 3x+ 2 * x
21 = 3x ^2 + 2x
Subtract 21 from both sides:
3x^2 + 2x -21 = 0
Use the quadratic formula to solve for x:
-2 +/- sqrt(2^2-4*3(-21))/(2*3)
X = 7/3 and -3
A dimension can’t be a negative value so x needs to be 7/3
Width = x = 7/3 = 2 1/3 cm
Length = 3(7/3) + 2 = 9 cm
Check: 9 x 2 1/3 = 21
Dimensions: width 2 1/3 cm length 9 cm
Answer:
yes the two triangles are similar
Answer:
yes
Step-by-step explanation:
Answer:
(-2, 1)
Step-by-step explanation:
consider the following equations: -x-y=1 y=x+3
For the lines to intersect, the values must be the same
-x-y=1
x + y = -1
y = -x - 1
Equating the y values
-x - 1 = x+ 3
-x-x = 3 + 1
-2x = 4
x = 4/-2
x = -2
Substitute x = -2 into y = x+3
y = -2 + 3
y = 1
Hence the required coordinate is (-2, 1)
