Answer:
61 commuters must be randomly selected to estimate the mean driving time of Chicago commuters.
Step-by-step explanation:
Given : We want 95% confidence that the sample mean is within 3 minutes of the population mean, and the population standard deviation is known to be 12 minutes.
To find : How many commuters must be randomly selected to estimate the mean driving time of Chicago commuters?
Solution :
At 95% confidence the z-value is z=1.96
The sample mean is within 3 minutes of the population mean i.e. margin of error is E=3 minutes
The population standard deviation is s=12 minutes
n is the number of sample
The formula of margin of error is given by,

Substitute the value in the formula,




Squaring both side,

Therefore, 61 commuters must be randomly selected to estimate the mean driving time of Chicago commuters.
Answer:
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Step-by-step explanation:
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Answer:
72.51
Step-by-step explanation:
Given that :
Lab score % = 23%
Each Major test % = 22.5%
Final exam % = 32%
Score :
Lab score = 96
First Major test = 64
Second major test = 62
Final exam = 69
Hence,
Weighted average = Σ(weight % * score)
Weighted average = Σweight_1*score_1 +.. Weight_n * score_n)
(0.23 * 96) + (0.225 * 64) + (0.225 * 62) + (0.32 * 69) = 72.51
Answer:
no
Step-by-step explanation:
2 boxes of eggs = 1.30 × 2 = 2.60
1 bottle of juice = 2.60
he payed 10 and got 0.90 so he payed 9.10
9.10-2.60-2.60= 3.90 which is the price of the 3 baguettes so.... 3.90÷3= 1.30£ is the price for 1 baguette
10 to the negative sixth equals 1/60, and then times 4 equals 4/60 or 1/15