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3 years ago

14

hello need help asap!!! can you guys plss pls pls pls pls pls pls pls pls pls pls help me and try your best on this problem! tha

nk you !!!!

1 answer:

NemiM [27]3 years ago

7 0

Answer:

the zeros are always on the x aixs so it would be -6,-2

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How do I solve 14x+5=105

Stella [2.4K]

Answer:7.14

Don’t rely on me I tried. Might be wrong but there’s an app called photo math and it’ll help with equations just like this.

Step-by-step explanation:subtract 5 from 5 and subtract 5 from 105 because you want to get X by itself. There for 14x equals 100. Then divide both by 14. 14 cancels out and you get your answer.

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4 years ago

Which equation has a vertex at (0, 5) and focus of (three-halves, 5)?

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C

Step-by-step explanation:

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A well known pharmaceutical manufacturer is manufacturing a newly developed vaccine, and is concerned about variability in the i

Lana71 [14]

Answer:

a

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

b

$X^2 = 13.74$

c

The decision rule is

Reject the null hypothesis

d

The conclusion is

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Step-by-step explanation:

From the question we are are told that

The variance is $\sigma ^2 = 1.9$

The sample size is n = 30

The sample variance is $s^2 = 0.9$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

Generally the test statistics is mathematically represented as

$X^2 = \frac{ (n- 1 ) * s^2 }{ \sigma^2 }$

=> $X^2 = \frac{ (30 - 1 ) * 0.9 }{1.9 }$

=> $X^2 = 13.74$

Generally from the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 30 - 1$

=> $df = 29$

Generally from the chi distribution table the critical value of $\frac{\alpha}{2} \ and \ 1 - \frac{ \alpha }{2}$ at a degree of freedom of $df = 29$ is

$X^2 _{ \frac{\alpha }{2} , df } = X^2 _{ \frac{0.05 }{2} , 29 } = 45.7$

=> $X^2 _{ 1 - \frac{\alpha }{2} , df } = X^2 _{1 - \frac{0.05 }{2} , 29 } = 16.0 5$

Gnerally from the values obtained we see that

$X^2 < X^2 _{ 1 - \frac{\alpha }{2} , df }$ hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

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3 years ago

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Step-by-step explanation:

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