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Neko [114]
2 years ago
14

A rectangular swimming pool with a length of 18m and width of 8m is surrounded by a concrete patio. The patio is a uniform 3m wi

dth around the entire pool. What is the area of the patio
Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
6 0

The area of the patio is 192 m^{2}

<h3>What is area?</h3>

An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure. The square unit, which is frequently expressed as square inches, square feet, etc., is the accepted unit of area.

The word "area" refers to a free space. A shape's length and width are used to compute its area.

Length of swimming pool=18 m

Width of swimming pool=8 m

Area of swimming pool= 18*8 = 144m^{2}

Width of patio=3m

Total length of swimming pool=18+2(3)=24 m

Total width of swimming pool=8+2(3)=14 m

Total area=24*14=336 m^{2}

Area of patio= total area - Area of swimming pool

                     =336-144

                     =192 m^{2}

Learn more about area here:

brainly.com/question/25292087

#SPJ4

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Answer :D

2530

Question explanation:

115 * 22 = 2530.

<em>I'm truly sorry if this is incorrect - Answered by Lilo</em>

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Travis bought two plots of land at the beginning of 2000. When purchased, the smaller plot of land was valued at $20,000.00 and
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HAT MATH ARE U IN
i got part of it but it lost me the 
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3 years ago
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On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)
goldfiish [28.3K]

Answer:

f(x) > 0 over the interval (-\infty,-4)

Step-by-step explanation:

If  f(x)  is a continuous function,  and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from - \infty, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from - \infty to -3, since between the  values -4 and -3 the function adopts negative values.

6 0
3 years ago
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Find the equation of the line that is perpendicular to x - y = -5 and passes through (4, 7).
Ivanshal [37]
X - y = -5
-y = -x - 5
y = x + 5...slope here is 1. A perpendicular line will have a negative reciprocal slope. All that means is flip ur slope and change the sign. So our perpendicular line will have a slope of -1.

y = mx + b
slope(m) = -1
(4,7)...x = 4 and y = 7
now we sub and find b, the y int
7 = -1(4) + b
7 = -4 + b
7 + 4 = b
11 = b

so ur perpendicular equation is : y = -x + 11 <==
8 0
3 years ago
A seal went 25 feet below sea level to catch a fish. A sea lion dove 10 feet less than three times as deep as the seal to catch
vfiekz [6]

Answer:

65 feet below sea level.

Step-by-step explanation:

With the information provided, we can create the following equation for the position of the sea lion (p)

p = 3x - 10

In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...

p = (3 * 25) - 10

p = 75 - 10

p = 65

Finally, we can see that the sea lion's position is 65 feet below sea level.

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3 years ago
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