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Tanya [424]
3 years ago
10

HELP FAST !!!

Mathematics
2 answers:
leonid [27]3 years ago
7 0

Answer:

(x, y) = (9, 10)

Step-by-step explanation:

-8x + 7y = -2...... (1)

- 8x + 8y = 8......(2)

Multiplying on both sides of the equations (1) & (2) by 8 and 7 respectively, we find:

-64x + 56y = - 16...(3)

-56x + 56y = 56.....(4)

Subtracting equation (4) from equation (3), we find:

-64x + 56y = - 16

-56x + 56y = 56

+ - -

_____________

- 8x = - 72

x = - 72/-8

x = 9

Substituting x = 9 in equation (1), we find:

-8(9) +7y = - 2

-72 +7y = - 2

7y = 72 - 2

7y = 70

y = 70/7

y = 10

(x, y) = (9, 10)

sertanlavr [38]3 years ago
3 0

-56x + 49y= -14

- 56x + 56y=64

105y=50

y=0.48

-8x+7(0.48)=-2

-8x+3.36=-2

-8x=-5.36

x=0.67

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Harlamova29_29 [7]
5 groups of 4 students = 20 students????????????????
8 0
3 years ago
What is the normal square root of 20
eduard

Answer:

\displaystyle 2\sqrt{5}

Step-by-step explanation:

\displaystyle 2\sqrt{5} = \sqrt{[5][4]} \\ \\ 4,472135955 ≈ 2\sqrt{5}

I am joyous to assist you anytime.

7 0
3 years ago
n a particular day, the wind added 2 miles per hour to Alfonso's rate when he was cycling with the wind and subtracted 2 miles p
goldfiish [28.3K]
Recall your d = rt, or distance = rate * time

notice, the time he took to cover 63 miles with the wind, is the same amount of time he took against it with 51 miles only, let's say, he took "t" hours long
and he was cycling at a rate of "r"

thus    \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{with the wind}&63&r+2&t\\
\textit{against the wind}&51&r-2&t
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
63=(r+2)t\implies \cfrac{63}{r+2}=\boxed{t}\\\\
51=(r-2)t\\
----------\\
51=(r-2)\left( \boxed{\cfrac{63}{r+2}} \right)
\end{cases}

solve for "r"
8 0
3 years ago
The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5
Arada [10]

Answer:

Width = 15 inches             Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

A = Lx   (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

L = x + 5   (2)

Also The area of a rectangle can be represented by the equation x^2 + 5x = 300

so to find the width x we solve the equation

x^2 + 5x -300=0   (3)

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:

a=1\\b=5\\c=-300

Then:

x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}

x=\frac{-5\±\sqrt{25+1200}}{2}

x=\frac{-5\±\sqrt{1225}}{2}

x=\frac{-5\±35}{2}

x_1=\frac{-5+35}{2}  →  x_1=15

x_2=\frac{-5-35}{2}  →   x_2=-20

We take the positive solution x=15\ in

Now we use equation (2) to find L

L = x + 5

L = 15 + 5

L = 20\ in

8 0
4 years ago
(NEED HELP ASAP PLZ)
Genrish500 [490]

Answer:

g(x)

Step-by-step explanation:

just took the quiz

7 0
3 years ago
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