q + 12 - 2(q - 22) > 0 |use distributive property
q + 12 +(-2)(q) + (-2)(-22) > 0
q + 12 - 2q + 44 > 0 |combine like terms
(q - 2q) + (12 + 44) > 0
-q + 56 > 0 |subtract 56 from both sdies
-q > -56 |change the signs
<h3>q < 56</h3>
The rate in

<h3>How to find rate is riya applying mulch in m^3/m^2 ?</h3>
given that riya applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space.
we already know that 1m = 100cm.
so, each side of this cube is 100cm in length.
so,
To find what is the volume in cubic metres.

so, the rate is
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Disclaimer : This question was given incomplete on portal.Here is complete question.
Question : Riya is applying mulch to her garden.She applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space. At what rate is riya applying mulch in m^3/m^2
Answer:
Error Bound = 0.04
Step-by-step explanation:
Whenever we want to estimate parameter from a subset (or sample) of the population, we need to considerate that your estimation won't be a 100% precise, in other words, the process will have a random component that prevents us from always making the exact decision.
With that in mind, the objective of a confidence interval is to give us a better insight of where we expect to find the "true" value of the parameter with a certain degree of certainty.
The estivamative of the true difference between proportions was -0.19 and the confidence interval was [-0.23 ; -0.15].
The question also defines the error bound, as the right endpoint of the confidence interval minus the sample mean difference, so it's pretty straight foward:
Error Bound = 
The interpretation of this would be that we expect that the estimative for the difference of proportions would deviate from the "true" difference about
or 4%.
The answer is B. The data is similar throughout the line.