how do i write an equation of a quadratic formula when given the roots and y intercept? is there a formula i can plug the number
1 answer:
9514 1404 393
Answer:
y = -3x^2 +3x +6
Step-by-step explanation:
For roots p and q, the equation can be written as ...
y = a(x -p)(x -q)
The value of 'a' must be determined so that the product <em>apq</em> is equal to the y-intercept. One could say that the formula is ...
y = (y-intercept)/(pq)·(x -p)(x -q)
For your given values of p = 2, q = -1, y-intercept = 6, this becomes ...
y = 6/(2(-1))(x -2)(x +1)
y = -3(x^2 -x -2) . . . . . simplifying a bit
y = -3x^2 +3x +6
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Answer:
<em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
Step-by-step explanation:
Find the diagram attached
If line AC and BD intersects, then m<AED + m<DEC = 180 (sum of angle on a straight line is 180 degrees)
Given
m<AED = 16x+8
m<DEC = 76 degrees
16x + 8 + 76 = 180
16x + 84 = 180
16x = 180-84
16x = 96
x = 96/16
x = 6
Hence the value of x is 6
Hence the correct option is <em>No, he should have set the sum of ∠AED and ∠DEC equal to 180°, rather then setting ∠AED and ∠DEC equal to each other</em>
