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Anastasy [175]
3 years ago
15

Solve: 2(5-4A)=-2A+8-6A

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
The a cancels out and you are left with the answer in the picture

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Can I get help for my 3rd grader
andrew-mc [135]

Answer:

what is the question.

Step-by-step explanation:

I need the question

7 0
3 years ago
Read 2 more answers
An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers.​ So, 10 adult male passengers can have a m
disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that \mu = 160, \sigma = 35

Sample of 10:

This means that n = 10, s = \frac{35}{\sqrt{10}} = 11.07

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{158 - 160}{11.07}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0
3 years ago
Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Plz help Pl
erastovalidia [21]

Answer:

1. KLP + PLM = 180 degrees (straight line)

2. 3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. x = 27

Step-by-step explanation:

1. Notice that angle KLP + angle PLM is a straight line, so KLP + PLM = 180 degrees (straight line)

2. angle KLP = 3x, so

3x + angle PLM = 180 degrees

3. angle PLM = 180 - 3x

4. PMN = P + PLM (Exterior angle)

5. 2x + 72 = x + 180 - 3x

6. 5 gives 4x = 108, so x = 27

6 0
3 years ago
Read 2 more answers
If you prove that △ABD is congruent to △CDB, which general statement best describes what you have proved?
fredd [130]

Answer:

  A: Opposite sides of a parallelogram are congruent

Step-by-step explanation:

The only diagonal involved is BD, so none of the statements regrading diagonals has been proven. The only thing proven is ...

  AB ≅ CD . . . . opposite sides are congruent

  AD ≅ CB . . . . opposite sides are congruent

5 0
2 years ago
School started at 8:05
ivann1987 [24]

Question is Incomplete, Complete question is given below.

School started at 8:05 a.m and ended at 2:40 p.m. the work below shows Erica's calculation of the length of the school day

Which two errors did Erica make

A.She subtracted instead of adding the times

B.She subtracted the end time from the start time

C.She did not regroup on hours for 60 minutes to subtract the minutes

D.she did not account for a.m. and p.m. in the start and end times.

E.see switch to hours and minutes in both the start and end times

Answer:

B. She subtracted the end time from the start time and

D. She did not account for a.m. and p.m. in the start and end times.

Step-by-step explanation:

The school started at 8:05 a.m. and ended at 2:40 p.m.

And the length of the school day is calculated by Erica and it is shown in the attached photo.

See the attached photo.

Erica has done two errors which are  

B. She subtracted the end time from the start time and  

D. She did not account for a.m. and p.m. in the start and end times.

3 0
3 years ago
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