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2 years ago

If I ran 20 miles in 150 how long would it take to run 6 miles?

Mathematics

2 answers:

patriot [66]2 years ago

8 0

Answer:

45 / 4.5

Step-by-step explanation:

150/20=7.5

7.5*6=45

True [87]2 years ago

5 0

150 what? are you saying 150 mins or 1.50 mins?

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Please answer question with work ♥️

vova2212 [387]

Answer:

r=201

d = 77 1/2

Step-by-step explanation:

6) First multiply left and right by 16, to get rid of the fraction:

r - 25 = 11*16

Now add 25 left and right:

r = 11*16 + 25 = 201

7) Add 5 left and right

2/5 d = 31

multiply by 5/2

d = 31 * 5/2 = 77 1/2

3 0

3 years ago

Solve the equation sine Ф=0.6792 for 0°≤Ф≤360

Sergio [31]

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

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3 years ago

Find the height of the triangle in which A=192 cm^2

romanna [79]

Step-by-step explanation:

one second 12345678910

6 0

2 years ago

At an end- of-season sale, a kid's pool was on sale for $168 . A sign advertised that this was 20% off the original price. What

Bogdan [553]

Answer: $134.40

Step-by-step explanation: Just find 80% of 168. That is because 100 - 20 is 80. The question says 20% OFF.

7 0

2 years ago

Read 2 more answers

The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha

kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

$\mu = 3500 \times 0.0004 = 1.4$

The probability that 2 or fewer cars will be stolen is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466$

$P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452$

$P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335$

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

4 0

1 year ago