Answer:
<u>, where "n" is number of objects per page.</u>
Step-by-step explanation:
<em>The amount of objects each page could hold is given by dividing the amount of objects that you have, by the number of pages. </em>
<em>• Let the number of objects per page be "n".</em>
<em>Then, the equation that gives us the number of objects for each page, in such way that we have an equal amount of objects per page is:</em>
.
I'll do the first two to get you started
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Problem 1
A = 3 = starting value
B = 10 = ending value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (10-3)/3 ] * 100%
C = (7/3) * 100%
C = 2.3333333 * 100%
C = 233.33333%
C = 233.3%
The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.
<h3>Answer: 233.3% increase</h3>
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Problem 2
A = 9 = start value
B = 20 = end value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (20-9)/9 ] * 100%
C = (11/9)*100%
C = 1.2222222222*100%
C = 122.22222222%
C = 122.2%
<h3>Answer: 122.2% increase</h3>
Answer:
10x+391≥503
Step-by-step explanation:
let x = # of sets
If you need at least 503 knives, both the sets of knives and the initial amount we already have (391) must add to have a number of knives greater than or equal to the minimum required amount.
Answer:
3/5
Step-by-step explanation:
Answer:
31.43 oz
Step-by-step explanation:
12.40 + 8.03 + 11 = 31.43
