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STatiana [176]
2 years ago
15

Evaluate (16+a)+ 6b divided by 3 when a = 2 and b = 3

Mathematics
1 answer:
yawa3891 [41]2 years ago
4 0

Answer:   24

Step-by-step explanation:

Follow PEMDAS. Parentheses: 16+a, which is 18. There are no exponents so move on to multiplication. 6b. B is equal to 3, and 6x3 is 18. Next, division. 18/3 is 6. Now do addition so add together 18+6 which is 24.

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How much money should be deposited today in an account that earns 7% compounded semiannually so that it will accumulate to $11,0
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Answer:

$8950.37

Step-by-step explanation:

Use the compound amount formula A = P(1 + r/n)^(nt), in which P is the initial amount of money (the principal), r is the interest rate as a decimal fraction, n is the number of times per year that interest is compounded, and t is the number of years.

Here we have A = $11,000, n = 2, r = 0.07 and t = 3, and so:

$11,000 = P(1 + 0.07/2)^(2*3), or

$11,000 = P (1.035)^6

                                           $11,000        $11,000

Solving for P, we get P = ---------------- = ------------- = $8950.37

                                            1.035^6          1.229

Depositing $8950.37 with terms as follows will result in an accumulation of $11,000 after 3 years.

7 0
3 years ago
Please help due tomorrow All he help you Got
Lunna [17]
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3 0
3 years ago
Kwamee created a coffee blend for his cafe by mixing Kona beans and Fuji beans. Kona beans cost $11 per pound and Fuji beans cos
yKpoI14uk [10]
Let's use K for Kona and F for Fuji. The system of equations has to be a balanced system. For example, you can't mix the number of pounds of beans with the cost for each because pounds and dollars are different and you can only combine like terms...pounds with pounds and dollars with dollars. So let's start with the number of pounds. Since we don't know how much of each he bought we have the 2 unknowns, F and K, but we DO know that he bought 23 pounds total. So the first equation is
K + F = 23
Now let's see what we can do with the dollars. Again, we don't know how much he bought of each kind of coffee, but we do know that Kona beans cost $11 per pound and that Fuji beans cost $7.50 per pound, and we know that he spent a total of $197. So let's set that up:
11K + 7.50F = 197
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2 years ago
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Trava [24]
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3 years ago
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