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STatiana [176]
2 years ago
15

Evaluate (16+a)+ 6b divided by 3 when a = 2 and b = 3

Mathematics
1 answer:
yawa3891 [41]2 years ago
4 0

Answer:   24

Step-by-step explanation:

Follow PEMDAS. Parentheses: 16+a, which is 18. There are no exponents so move on to multiplication. 6b. B is equal to 3, and 6x3 is 18. Next, division. 18/3 is 6. Now do addition so add together 18+6 which is 24.

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Write an equation in standard form for the line, where the points (-2, -1) and (0, 4) are on the line
DedPeter [7]

Answer:

An equation in standard form for the line is:

\frac{5}{2}x-y=-4

Step-by-step explanation:

Given the points

  • (-2, -1) and (0, 4)

The slope between two points

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(0,\:4\right)

m=\frac{4-\left(-1\right)}{0-\left(-2\right)}

m=\frac{5}{2}

Writing the equation in point-slope form

As the point-slope form of the line equation is defined by

y-y_1=m\left(x-x_1\right)

Putting the point (-2, -1) and the slope m=1 in the line equation

y-\left(-1\right)=\frac{5}{2}\left(x-\left(-2\right)\right)

y+1=\frac{5}{2}\left(x+2\right)

y=\frac{5}{2}x+4

Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

so

y=\frac{5}{2}x+4

\frac{5}{2}x-y=-4

Therefore, an equation in standard form for the line is:

\frac{5}{2}x-y=-4

7 0
2 years ago
A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w
hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = \pi r^2h

V=3.14\times (0.5 m)^2\times 5 =3.925 m^3

Mass of gasoline = m

Density of gasoline = d = 673 kg/m^3

m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g .8 m/s^2

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

W =m\times g\times h

W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

6 0
3 years ago
Round to the nearest thousand then subtract
grin007 [14]
6000 - 600

If u subtract dis, it would be 5400 :)
5 0
2 years ago
Read 2 more answers
What is the simplest form of Negative 0.14 in a mixed number
Kazeer [188]
0.14 = 14/100 = 7/50
7 0
3 years ago
Find the slope of the line through each pair of points for questions 21 to 39​
likoan [24]

Answer:

23,24,26,27 sorry if you get it wrong

6 0
3 years ago
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