3 years ago

Can some one answer this

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

7 0

Answer:

Step-by-step explanation

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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

Need help with this answer

ioda

Answer:

(2,2) is your answer :)

Step-by-step explanation:

3 0

3 years ago

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Dafna11 [192]

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Ulleksa [173]

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The answer should be the last one

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3 years ago

Help me please...I will mark brainliest

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The answer is A because playing sport is not affected by playing sports (for more detail go to https://www.mathsisfun.com/data/probability-events-independent.html)

If it's not A then it's B

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3 years ago