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Romashka [77]
3 years ago
6

Two cities have nearly the same​ north-south line of 110 degrees Upper W. The latitude of the first city is 23 degrees Upper F c

ommand the latitude of the second city is 36 degrees N. Approximate the distance between the cities if the average radius of Earth is 6400 km.
Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

CORRECTED QUESTION:

Two cities have nearly the same​ north-south line of 110 degrees Upper W. The latitude of the first city is 23 degrees Upper N, and the latitude of the second city is 36 degrees N. Approximate the distance between the cities if the average radius of Earth is 6400 km.

ANSWER: 1452.11 km

Step-by-step explanation:

Since the two cities both lies on the Northern latitude of the sphere along  the same longitude, we are going to subtract the angles the latitude that each city subtend at the equator.

36 - 23 = 13 degrees   i.e the angles between the with two cities on a cross section the large circle formed by the longitude and its center.

Applying   the formula for the length of an arc on a sector on the large circle  

(∅/ 360) x 2πR

where, ∅ = is the angle between the two cities

R = radius of the Earth.

13/360 x 2 x π x 6400 = 1452.11 km

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In the given question, there are several data of immense importance. based on these data's the answer to the question can be easily deduced. it is already given that the total utility bill for the month of April in Millers house is $132 and 42% of the bill was paid for gas. remaining amount is paid as electricity charges.
Now
Amount of money paid for gas = 132 * (42/100) dollars
                                                  = 5544/100 dollars
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The amount of money paid for electricity = (132 - 55.44) dollars
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So the Millers paid 55.44 dollars for gas and 76.56 dollars for electricity in the month of April.
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3 years ago
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Answer:

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And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

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And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

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n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

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