Help:) pls last question

My brother needs help with his math homework and I don't understand this?need help.

Olin [163]

To answer the problems correctly, you have to follow and pay close attention to whether or not it says "Area" or "Perimeter". For example, for the first problem, area of 63 square units, you would have to create a shape thats sides multiply out to equal 63 units squared. He could draw a square with 9 units by 7 units. This would work because 9x7=63. For perimeter, all four sides must add up to equal 38 units. Feel free to get creative with the shape on this one! If you have any other questions, just ask. Hope I helped some. :)

7 0

3 years ago

Nico, Aditi, Erick, Raj, and Sandra are solving the equation.

Alex777 [14]

Answer:

Nico, Raj and Sandra are correct

Step-by-step explanation:

we have

$\frac{2}{5}(5+x)=8$

Method 1

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Multiply by 5/2 both sides

$(\frac{5}{2})\frac{2}{5}(5+x)=(\frac{5}{2})8$

$5+x=20$

subtract 6 both sides

$5+x-5=20-5$

$x=15$

Method 2

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Multiply by 1/2 both sides

$(\frac{1}{2})\frac{2}{5}(5+x)=(\frac{1}{2})8$

$\frac{1}{5}(5+x)=4$

Multiply by 5 both sides

$(5)\frac{1}{5}(5+x)=(5)4$

$5+x=20$

subtract 6 both sides

$5+x-5=20-5$

$x=15$

Method 3

Solve for x

That means ----> isolate the variable x

we have

$\frac{2}{5}(5+x)=8$

Apply distributive property left side

$\frac{2}{5}(5)+\frac{2}{5}(x)=8$

$2+\frac{2}{5}(x)=8$

subtract 2 both sides

$2+\frac{2}{5}(x)-2=8-2$

$\frac{2}{5}(x)=6$

Multiply by 5/2 both sides

$(\frac{5}{2})\frac{2}{5}(x)=(\frac{5}{2})6$

$x=15$

therefore

Nico, Raj and Sandra are correct

6 0

4 years ago

Read 2 more answers

A tennis coach divides her 9-player squad into three 3-player groups with each player in only one group. How many different sets

Roman55 [17]

Answer:

84

9 choose 3

Step-by-step explanation:

8 0

3 years ago

A 1125 ft^3 open-top rectangular tank with a square base x ft on a side and y ft deep is to be built with its top lush with the

nikdorinn [45]

Answer:

The values of x and y that will minimize the cost is 15 ft and 5 ft respectively and the minimum cost will 3,375

Step-by-step explanation:

With a 1125 ft^3 open-top rectangular tank with a square base x ft on a side and y ft deep is to be built with its top lush with the ground to catch runoff water, x is the length, y is the height;

x^2*y = 1125

y = 1125/x^2 ----(1)

The total cost of c = 5(x^2 + 4xy) + 10xy

Then,

c = 5(x^2 + 4x*(1125/x^2)} + 10x*(1125/x^2)

c = 5x^2 + 22,500/x + 11,250/x

c = 5x^2 + 33,750/x

To minimize the cost of c, find the derivatives of c; c'

c' = 10x - 33,750/x^2

c' = (10x^3 - 33,750)/x^2

c'(x) = 0; 10x^3 = 33,750

x = ³√33,750 = 15

x = 15; y = 1125/x^2

y = 1125/15^2 = 5

(x,y) = (15,5)

c = 5x^2 + 33,750/x

c = 5*15^2 + 33,750/15 = 3,375

The values of x and y that will minimize it is 15 ft and 5 ft respectively and the minimum cost will 3,375

8 0

3 years ago

A photo of an ant in a science book is increased 565% as large as the actual size. If the ant is 14 millimeters, what is the siz

murzikaleks [220]

Answer:

93.1 millimeters is the size of the ant in the photo.

Step-by-step explanation:

Given:

A photo of an ant in a science book is increased 565% as large as the actual size.

If the ant is 14 millimeters.

Now, to find the size of the ant in the photo.

The actual size of ant = 14 millimeters.

The size of the ant in the photo is increased 565% of 14 millimeters.

Now, to get the size of the ant in the photo we put an expression:

According to question:

$14+565\%\ of\ 14\\\\=14+\frac{565}{100}\times 14\\\\=14+5.65\times 14\\\\=14+79.1\\\\=93.1\ millimeters.$

Therefore, 93.1 millimeters is the size of the ant in the photo.

8 0

4 years ago