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Angelina_Jolie [31]
2 years ago
10

Can u pls help solve by using trig

Mathematics
1 answer:
Monica [59]2 years ago
8 0

Answer:

32.485

Step-by-step explanation:

24+6root2

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If you can help with any of these two or both that would be great ! :) <br> thanks
Vladimir [108]

Answer:

hmmm not sure

Step-by-step explanation:

try mulitply the numbers

7 0
2 years ago
A-One Talent Agency has 108 clients. 42 of the clients play piano and 51 of the clients play guitar.
Butoxors [25]

Thwre are 28 clients who don not play any of the instrument using the principle of Venn distribution.

<u>Using a Venn diagram analogy</u> :

  • Total number of client, U = 108
  • Piano, P = 42
  • Guitar, G = 51
  • Piano and Guitar, (PnG) = 13
  • None =?

<u>From the information given</u> :

  • P only = 42 - 13 = 29
  • G only = 51 - 13 = 38

<u>The total number of clients can be related thus</u> :

  • Total = P only + G only + PnG + None

108 = 29 + 38 + 13 + None

108 = 80 + None

None = 108 - 80

None = 28

Therefore, the number of clients who do not play any of the instruments is 28

Learn more :brainly.com/question/12570490

7 0
2 years ago
What is the amplitude of this function f(x) ? f(x)=34cos(3x)+4
jeyben [28]

Answer:

The amplitude is 34. So therefore your answer is 34.

Step-by-step explanation:

Vertical Shift: 4

Amplitude: 34

Period: 2pi/3

3 0
2 years ago
1. 4x + 3(x-9) = 19
Dmitry_Shevchenko [17]

1) 4x + 3(x-9) = 19

or, 4x + 3x - 27 = 19

or, 7x = 19+27

or, 7x = 46

or, x = 46/7

◆ x = 6.57

2) 2(x-4) + 5x = 3

or, 2x - 8 + 5x = 3

or, 7x = 3+8

or, x = 11/7

◆ x = 1.57

3) 60 = 8y - 3(y-10)

or, 60 = 8y - 3y + 30

or, 60 - 30 = 5y

or, y = 30/5

◆ y = 6

4) 40 + 3c = 3 + 9(c-2)

or, 40 + 3c = 3 + 9c - 18

or, 40 + 3c = 9c - 15

or, 9c - 3c = 40 + 15

or, 6c = 55

◆ c = 9.166

I hope you understand..

Thank you...♥♥

5 0
2 years ago
Read 2 more answers
140 subtracted from the square of a number the result is three times the number find the negative solution
natima [27]

Answer:

Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.

5 0
3 years ago
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