Let S represent the cost of a small box, and L represent the cost of a large box.
Matt's sale can be represented by the equation
3S +14L = 203
Ming's sale can be represented by the equation
11S +11L = 220
There are a number of ways to solve a pair of equations. One is to graph them. The graph shows the costs to be ...
The cost of a small box of oranges is $7. The cost of a large box of oranges is $13.
Answer:
Answer is C
Step-by-step explanation:
When we do the vertical line test the line intersects (cause its a circle)
This could explain better

First, let's deal with the fraction in the denominator of the exponent. Multiply the top and bottom of the exponent by 6.

Now that the fraction in the denominator is taken care of, we can reduce the denominator.
. Some professors might accept this as simplest form, but others might ask you to get rid of the negative.

Step-by-step explanation:
5^2 + b^2 = 9^2
25 + b^2 = 81
b^2 = 56
square root both sides and b = 7.48 cm