Write the standard form for 25

A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod

tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1 2 3

495 525 470

500 515 480

505 505 460

500 515 470

∑2000 2060 1880

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4= 470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using μ ± σ , μ±2 σ or μ ± 3 σ.

In this question the limits are determined by using μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4= 470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0

2 years ago

Identify whether the series is a convergent or divergent geometric series and find the sum, if possible. A) This is a convergent

Darya [45]

A divergent series is a type of series in which the ratio is too large and the summation is held from one to infinity. Hence, the sum could not be found out. A convergent series, on the other hand, has a definite answer because one could be the ratio is small and the lower and upper limits are defined not equal to infinity either positive or negative.

7 0

3 years ago

What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2

frez [133]

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We ahve the slope m = 1/2 and the point (-2, 1). Substitute:

$y-1=\dfrac{1}{2}(x-(-2))$

$y-1=\dfrac{1}{2}(x+2)$ - point-slope form

Covert to the slope-intercept form (y = mx + b):

$y-1=\dfrac{1}{2}(x+2)$ use the distributive property

$y-1=\dfrac{1}{2}x+1$ add 1 to both sides

$y=\dfrac{1}{2}x+2$ - slope-intercept form

Convert to the standard form (Ax + By = C):

$y=\dfrac{1}{2}x+2$ multiply both sides by 2

$2y=x+4$ subtract x from both sides

$-x+2y=4$ change the signs

$x-2y=-4$ - standard form

Convert to the general form (Ax+By+C=0):

$x-2y=-4$ add 4 to both sides

$x-2y+4=0$ - general form

5 0

3 years ago

Pretty please help this work is hard

Arlecino [84]

Answer:

Parentheses, exponents, multiplication and division, and addition and subtraction

Step-by-step explanation:

You can remember this order by using PEMDAS. PEMDAS stands for parentheses, exponents, multiplication, division, addition, and subtraction, in that order. First up should be parentheses, then exponents, then multiplication and division, and finally addition and subtraction.

6 0

3 years ago

Please help Solve for x.

Olegator [25]

Sum of interior angles = (n-2) × 180 = (5-2) x 180 = 3 x 180 = 540

so
x + 90 + 107 + 144 + 138 = 540
x + 479 = 540
x = 540 - 479
x = 61

5 0

3 years ago