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mina [271]
3 years ago
11

Quadrilateral ABCD is inscribed in a circle. Angle B measures 19°. What is the measure of angle D?

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

D = 161^o

Step-by-step explanation:

Given

\angle B = 19^o

Required

Find D

The label of the quadrilateral are not clear. However, a more complete question illustrates that B and D are opposite sides.

To solve for D, we make use of:

B + D = 180^o ---- opposite sides of a cyclic \\ quadrilateral

Make D the subject

D = 180^o -B

D = 180^o -19^o

D = 161^o

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X+ y = 44
x - y = 6
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2x = 50

x = 25
y = 44-x = 19
3 0
3 years ago
Pls help, solve for a.
vovangra [49]
A equals -1/2 is the right answer
5 0
3 years ago
If k + 1, 2k - 1 and 3k + 1 are three consecutive terms of a GP, find the value of the common ratio​
eduard

Answer:

r = -1 or r = 5/3

Step-by-step explanation:

(2k - 1)/(k + 1) = (3k + 1)/(2k - 1)

(2k - 1)^2 = (k + 1)(3k + 1)

4k^2 - 4k + 1 = 3k^2 + 4k + 1

k^2 - 8k = 0

k(k - 8) = 0

k = 0 or k = 8

For k = 0,

(2k - 1)/(k + 1) = -1/1 = 1

For k = 8,

(2k - 1)/(k + 1) = 15/9 = 5/3

6 0
3 years ago
Part A: Plot the points A(-8,7) and B(6,-9). Mark the halfway point on AB and label it point M. What are the coordinates of M? P
vredina [299]

Answer:

a. M(x,y) = (-1,-1)

b. D(-4,-9)

Step-by-step explanation:

Given

A(-8,7) and B(6,-9).

Solving (a):

Determine the Midpoint M;

This is calculated as follows;

M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Where

(x_1,y_1) = (-8,7)

(x_2,y_2) = (6,-9)

Substitute these values in the formula

M(x,y) = (\frac{-8+6}{2},\frac{7-9}{2})

M(x,y) = (\frac{-2}{2},\frac{-2}{2})

M(x,y) = (-1,-1)

<em>Hence; the midpoint is (-1,-1)</em>

Solving (a):

Here, we have

C = (2,7)

M; Midpoint = (-1,-1)

Required: Determine D

This is calculated as follows;

M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Where

(x_1,y_1) = (2,7)

(x,y) = (-1,-1)

Substitute these values in the formula

(-1,-1) = (\frac{2+x_2}{2},\frac{7+y_2}{2})

Solving for x2

-1 = \frac{2 + x_2}{2}

Multiply both sides by 2

-2 = 2 + x_2

Subtract 2 from both sides

x_2 = -2 - 2

x_2 = -4

Solving for y2

-1 = \frac{7 + y_2}{2}

Multiply both sides by 2

-2 = 7 + y_2

Subtract 7 from both sides

y_2 = -2 - 7

y_2 = -9

Hence, the coordinates of D is

D(-4,-9)

7 0
4 years ago
Which of the following statements is not true about this graph?
agasfer [191]
B. It is not true. The point at x=0 is not part of a solution for the piece wise function.
3 0
3 years ago
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