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3 years ago

1- Name the Circle3- Name Two Chords5- Name a tangent

Mathematics

1 answer:

Gnoma [55]3 years ago

7 0

Answer:

Name: Circle A

Chords: Chord DP, Chord HC

Tangent: EFG

Step-by-step explanation:

Name a circle by the center, in this case it's A.

Chord: A chord is a line only in the circle, not outside of it, and its endpoints are right on the circle.

Tangent of a circle: "Tangent" means touching, and this is a line, in terms of a circle, that touches the circle but is not INSIDE of the circle.

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Can someone help me out with this

katen-ka-za [31]

Answer:

$AB=4.41$

Step-by-step explanation:

Use the cosine ratio, $cosine=\frac{adjacent}{hypotenuse}$ . Insert the values:

$cos25=\frac{4}{x}$

Isolate x. Multiply both sides by x:

$x*(cos25)=x*(\frac{4}{x})\\\\x*cos25=4$

Divide both sides by cos 25:

$\frac{x*cos25}{cos25}=\frac{4}{cos25}\\\\x=\frac{4}{cos25}$

Insert into a calculator:

$x=4.414$

Round to the nearest hundredth:

$x=4.41$

Done.

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3 years ago

What is the solution to the inequality?

fiasKO [112]

B. x > -4 I did da test. That's da correct one :-)

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3 years ago

HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-

Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

$f(x) =2x^3-9x^2+13x-6$

If x+1 is a factor , then f(-1) must evaluate to zero.

$f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6$

$f( - 1) =2( - 1)-9( 1)+13( - 1)-6$

$f( - 1) = - 2-9 - 13-6$

$f( - 1) = -11 - 19$

$f( - 1) = - 30$

Since f(-1) is not equal to zero, x+1 is not a factor of

$f(x) =2x^3-9x^2+13x-6$

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4 years ago

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konstantin123 [22]

Answer:

the answer is the option C

m∠2 = 99° and m∠4 = 99°

Step-by-step explanation:

edg 2020

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3 years ago

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Leviafan [203]

Hope this is straightforward.

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3 years ago