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3 years ago

Help please

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

Draw a circle chart, then try to map out the answer. I cant make a virtual one

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Hi everyone , Would you help me please :

Veseljchak [2.6K]

$\displaystyle \\ 
 \frac{1}{ \sqrt{2} } = \frac{1 \times \sqrt{2}}{ \sqrt{2} \times \sqrt{2}} = \boxed{\frac{\sqrt{2}}{2}}$

8 0

3 years ago

What is -4 2/3 as a decimal with work

Luba_88 [7]

The decimal equivalent is -4.666....

In order to find this, we need to start by just taking the whole number for itself.

-4.

Now we have to handle the fraction version. In order to do that, we need to do the division and turn into a decimal.

2/3 = .666...

Now we simply put them together and get our answer.

-4.666...

6 0

3 years ago

"Can anyone help me?<br><br><img src="https://tex.z-dn.net/?f=helppp%20%5C%3A%20me" id="TexFormula1" title="helppp \: me" alt="h

Cloud [144]

i cant read it clearly

4 0

3 years ago

Find the missing denominator or numerator of 1/2 = /4

Jet001 [13]

Simply cross-multiply about,

$\bf \cfrac{1}{2}=\cfrac{x}{4}\implies 4\cdot 1=2\cdot x\implies 4=2x\implies \cfrac{4}{2}=x\implies 2=x$

6 0

3 years ago

Read 2 more answers

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

3 years ago