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Ira Lisetskai [31]
3 years ago
5

Solve by substitution 9x+6y=18 6x+6y=24

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

x= -2 , y= 6 is the answer

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Someone help pls i will mark u brainliest
Alla [95]

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Step-by-step explanation:

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A cookie factory uses 1/3 of a bag of flour in each batch of cookies. The factory used 2/3 of a bag of flour yesterday. How many
Mumz [18]

Answer:

They made 2 batches

Step-by-step explanation:

If the factory used ⅔, and 1 batch is ⅓, the factory made 1 batch for each 3rd they used. ⅔, 2 batches

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3 years ago
An equation that defines y as a function of x is given. a. solve for y in terms of x and
Ymorist [56]

Answer:

  • f(x) = 2x -2/3
  • f(3) = 5 1/3

Step-by-step explanation:

We solve an equation for a specific variable by using inverse operations to undo what is done to the variable. The resulting function is evaluated by substituting the given value for the variable.

__

<h3>a.</h3>

We are given the equation ...

  6x -3y = 2

Solving for y, we get ...

  6x -2 = 3y . . . . . add 3y-2 to both sides

  2x -2/3 = y . . . . . divide by 3

  f(x) = 2x -2/3 . . . . write using functional notation

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<h3>b.</h3>

To find f(3), we use x=3 in the function.

  f(3) = 2(3) -2/3 = 6 -2/3

  f(3) = 5 1/3

4 0
2 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
Does anyone know the answer?
Alexxandr [17]

Hello from MrBillDoesMath!

Answer:

88

Discussion:

Angle Q is an inscribed angle so

    measure angle Q = 44  =

                      (1/2) measure of intercepted arc.

In other words,

44 = 1/2 mST               =>   multiply both sides by 2

m ST = 44*2 = 88

which is the second choice

Thank you,

MrB

5 0
3 years ago
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