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snow_lady [41]
3 years ago
8

In the sale, jumpers are on the offer “buy 2, save 1

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:Step-by-step explanation:

so if you buy 2 jumpers it will be the cost of 1

and 30% of 50 is 15 so 15 + 15 = 30 plus 45 =

75

Art [367]3 years ago
7 0

Answer:

75$

Step-by-step explanation:

so if you buy 2 jumpers it will be the cost of 1

and 30% of 50 is 15 so 15 + 15 = 30 plus 45 =

75$

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The temperature was -3° last night it is now -4° see what was the change in temperature was-3° C. It is -4° C. What was the chan
raketka [301]

Answer:

The temp got colder by -1

Step-by-step explanation:

The difference of -3 to -4

-4 + -3 = -1

7 0
3 years ago
Select the answer choice that equals the given expression. 8^-3 x 8^-2 x ^5
Alexus [3.1K]

Answer:

B) 1

Step-by-step explanation:

Given:

8^{-3}\times 8^{-2}\times8^5

We need to solve the given expression.

Now We know that when base of the exponents then the law of indices applied for the same.

Now According to Law of Indices.

x^a\times x^b = x^{a+b}

On Solving the above expression we get;

8^{-3+(-2)+5}\\\\8^{-3-2+5}\\\\8^{-5+5}\\\\8^0\\\\\textrm{Now Again by law of indices;}\\\\a^0 =1\\\\Hence\ 8^0 = 1

Hence The Simplified form of given expression is 1.

5 0
3 years ago
A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
What is the domain of y = log Subscript 4 Baseline (x + 3)?
LekaFEV [45]

Answer:

All real numbers greater than -3

Step-by-step explanation:

The domain of a log is the baseline is greater than 0.

Set x + 3 greater than zero and solve

x + 3 > 0

x > -3

3 0
2 years ago
7.EE.1.1
victus00 [196]

Answer:

-0.55n - 0.05

Step-by-step explanation:

You can start by distributing:

(0.25n - 0.3) - (0.8n - 0.25)

0.25n - 0.3 - 0.8n + 0.25

Then, you can combine like terms(0.25n & -0.8n; -0.3 & 0.25)

-0.55n - 0.05

4 0
3 years ago
Read 2 more answers
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