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shutvik [7]
4 years ago
5

What is the angle of depression from the start of a 6-foot high access ramp that ends at a point 40 feet away along the ground?

Nearest tenth of a degree.
Mathematics
1 answer:
Mars2501 [29]4 years ago
3 0

Answer:

<h3>8.5 degrees</h3>

Step-by-step explanation:

The set up will give a right angles triangle;

Given

The height of the ramp (opposite) = 6 foot

distance away along the ground = 40 feet (adjacent)

Required

Angle of depression theta

Using the TOA identity;

tan theta = opposite/adjacent

tan theta = 6/40

tan theta = 0.15

theta = tan^-1{0.15}

theta =8.53 degrees

hence the angle of depression to nearest tenth of a degree is 89.5 degrees

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A rectangular prism is completely packed with 63 cubes of edge length fraction 1 over 3 inch, without any gap or overlap.
77julia77 [94]

Answer:

  2 1/3 cubic inches

Step-by-step explanation:

Perhaps you want to know the volume of the prism in cubic inches.

Find the total volume of the smaller cubes:

  63(1/3 in)^3 = 63/27 in^3 = 7/3 in^3 = 2 1/3 in^3

4 0
3 years ago
Solve for x in the triangle<br> A 25.6<br> B 27.8<br> C 45.6<br> D 64.4
labwork [276]

Answer:

The measure of angle x is 64.4\°

Step-by-step explanation:

To find the measure of angle X, apply the law of cosines

The law of cosines states that

c^{2}=a^{2}+b^{2}-2(a)(b)cos(C)

In  this problem we have

a=19\ cm

b=25\ cm

c=24\ cm

C=x\°

substitute

24^{2}=19^{2}+25^{2}-2(19)(25)cos(C)

576=986-950cos(C)

cos(C)=(986-576)/950

C=arccos[(986-576)/950]=64.4\°

Therefore

The measure of angle x is 64.4\°

7 0
4 years ago
What are the coordinates of the vertices of the pre-image given? ry= −x ◦ T1, −2(x, y) 
nataly862011 [7]
<h3><u>Answer:</u></h3>

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

<h3><u>Step-by-step explanation:</u></h3>

We have to find the  coordinates of the vertices of the pre-image given?

Ry= −x ◦ T_1, −2(x, y)

i.e. we have to find the composition of reflection along the line y=-x and translation with the rule:

(x,y) → (x+1,y-2)

Now we have coordinates of A",B",C" and D" as:

A"(-4,-2)

B"(-2,-1)

C"(-2,-4)

D"(-4,-3)

Now we are asked to find the coordinates of the pre-image.

Also when any point is reflected along y=-x then the point is transformed to:

(x,y) → (-y,-x)

Let A,B,C and D are the points of the pre-image.

Hence, the coordinates of the pre-image are given as:

so, the transformation is given as:

A→A'→A"

B→B'→B"

C→C'→C"

D→D'→D"

Where A',B',C',D' represents the transformation after translation and A",B",C",D" represents the transformation after reflection as well.

The coordinates of A' are (2,4)

B' are (1,2)

C' are (4,2)

and D' are (3,4)

Now, the coordinates of pre-image are given as:

A'(x,y)  → A(x-1,y+2)=A(1,6)

B'(x,y)  → B(x-1,y+2)=B(0,4)

C'(x,y)  → C(x-1,y+2)=C(3,4)

and D'(x,y)  → D(x-1,y+2)=D(2,6)

Hence, the coordinates of pre-image are:

A(1,6) , B(0,4) , C(3,4) , D(2,6)

4 0
3 years ago
Please answer this question !! 20 points and brainliest !! Thank u !!
Ostrovityanka [42]

Answer:

Step-by-step explanation:

The system of equations (a) is the correct one for this situation.  We must now solve this system for x and y, which are the unit costs.

Multiplying the 2nd equation by (-3/2) yields -12x - 18y = -168.

Now eliminate x by combining the two equations

12x + 5 y = 116

-12x  -18y  = - 168

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If y = 4 then 12x + 5y = 116, or

                    12x  +5(4) = 116, or

                     12x  +  20  =  116, or

                      12x       = 96, or x = 8

Roller pens are $8/dozen and ball point pens are $4 per dozen.

5 0
4 years ago
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aniked [119]
Because u just put the 2.11 in that order
7 0
3 years ago
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