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3 years ago

5 times 5 divided by 2

Mathematics

2 answers:

Vesna [10]3 years ago

8 0

5 x 5 / 2 This problem is super easy because i am in Kamehameha Schools and the answer to this problem is 12.5

AlekseyPX3 years ago

3 0

5x5=25 25/2=5
The answer is 5

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Angelica earns d dollars for babysitting each week. She also receives an allowance of $10 per week. The expression (10+d)∙5 can

Katyanochek1 [597]

Answer:

The amount of money Angelica will have at the end of five weeks if d = $25 is $175.

Step-by-step explanation:

The given information are;

The allowance Angelica earns for baby sitting = d dollars per week

The amount she receives as allowance = $10 per week

The amount she will have at the end of 5 weeks = (10 + d)·5

The amount, A, of money Angelica will have at the end of five weeks if d = $25 is given as follows;

A = (10 + 25) × 5 = $175

The amount of money Angelica will have at the end of five weeks if d = $25 is $175.

7 0

3 years ago

Which of the following equations is equivalent to log(y)= 3.994 ?

Kisachek [45]

Answer:

The correct answer is option D: $y = 10^{3.994}$

Step-by-step explanation:

Given:

log(y)= 3.994

Solution:

A logarithm base b of a positive number x satisfies the following definition:

$y =log_b(x) => b^y =x$

For $x > 0, b >0, b \neq 1$

Also if no base b is indicated, the base of the logarithm is assumed to be 10 .

Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10

now

$log_{10}(y)= 3.994$

Then

$y = 10^{3.994}$

4 0

3 years ago

Can someone help me for this?

Ludmilka [50]

Answer:

500000N=2m

x. =6m

cross multiply, it'll be

6×50000÷2

=150,000N

8 0

2 years ago

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

2 years ago

Read 2 more answers

5/6 + 2/3 + 1/4 = ???

jeka94

7/4 is the answer to your question

6 0

2 years ago