I will answer if u post the ?s in a coment
<span>We can safely assume that 1212 is a misprint and the number of seats in a row exceeds the number of rows by 12.
Let r = # of rows and s = # of seats in a row.
Then, the total # of seats is T = r x s = r x ( r + 12), since s is 12 more than the # of rows.
Then
r x (r + 12) = 1564
or
r**2 + 12*r - 1564 = 0, which is a quadratic equation.
The general solution of a quadratic equation is:
x = (-b +or- square-root( b**2 - 4ac))/2a
In our case, a = 1, b = +12 and c = -1564, so
x = (-12 +or- square-root( 12*12 - 4*1*(-1564) ) ) / 2*1
= (-12 +or- square-root( 144 + 6256 ) ) / 2
= (-12 +or- square-root( 6400 ) ) / 2
= (-12 +or- 80) / 2
= 34 or - 46
We ignore -46 since negative rows are not possible, and have:
rows = 34
and
seats per row = 34 + 12 = 46
as a check 34 x 46 = 1564 = total seats</span>
The smallest one is -2/7
The largest one is 8/9 The difference between them is
8/9 - - 2/7 =
8/9 + 2/7 =
7*8/9*7 + 2*9/9*7 =
56 / 63 + 18 / 63 =
74 / 63 =
1 11/63
It is correct because if you do the math you will come up with 48 - 24k = 48 - 24k
2c+3d=900
C=x
D=350-x
2x+3 (350-x)=900
Solve for x to get number of children
attended the fair that day
2x+1050-3x=900
2x-3x=900-1050
-1 x=-150
x=150 children
350-150=200 adult
