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polet [3.4K]
3 years ago
6

How to determine if something is a linear transformation?

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0
A linear transformation is a function T:R^n-->R^m that satisfies the following properties 
1.T(x+y)=T(x)+T(y)
2.T(ax)=aT(x)
i hoped this helped i honestly tried . let me know if im missing something 
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Find the solution to the syster<br> y = 2x = 5<br> y = X - 2
lana66690 [7]

Answer:

Both of these equations are in slope-intercept form. The slope-intercept form of a linear equation is: y=mx+b

Where m is the y-intercept value.

y=-2x+5

y=-2x+20

The slope of the two equations are: m1=−2 and m2=−2

Step-by-step explanation:

Because the have the same slope it means the lines represented by these two equations are either parallel or are the same line.

The y-intercepts for the two lines are:b1 = 5 and b1=20

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2 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
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