The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).
We will write cubic inches as three inches side-by-side
350 in^3
<h3>What is the ratio of the centimeter?</h3>
This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in
So, we can cancel the three inches top and bottom thus we have the answer in centimeters cubed. And the value is
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.
So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).
This is larger than a 5500 cubic centimeters engine.
5735.5-5500=235.5cubic centimeters.
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
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$5000 I think should be right
The probabilities of all possible outcomes in a distribution must sum to 1.

Answer:
9.797. . .
Step-by-step explanation:
2/3 of 144 is 96

Answer:
2x + 6 = -18
x + 1 = -11
3x = -36
Step-by-step explanation:
First find the solution! Then you can create your own equations
2x+9=-15
2x=-24
x=-12
Thus u need solutions with:
x = -12
Knowing the equation of a line as:
y = mx + b
we can can start by making y = -12 (our solution)
mx + b = -12
Now we can pick a value for m and b by adding and miltiplying on both sides
We do this to keep both sides equal.
if we make m = 2 and b = 3:
2x + mb = -12*m + 2b
2x + 6 = -24 + 6
2x + 6 = -18
Solving this we also get x = -12, as we expect.
An alternative way to think about it is to imagine that we start with a simple equation and make it more complex. We have our solution:
x = -12 => lets add a b value!
x + b = -12 + b => Lets add a slope (m)
xm + bm = -12m + bm
Giving values for this can give you multiple equation of the same solution.
General Formula:
m(x+b) = m(y+b)
mx + bm = my + bm