Answer:
∠MPQ ≅ ∠MPR: Reason; Corresponding parts of congruent triangles are congruent (CPCTC)
∠PQR ≅∠PRQ: Reason; CPCTC
Step-by-step explanation:
: Reason; Given
Draw
so that M is the midpoint of
: Reason; Two points determine a line
: Reason; Definition of midpoint
: Reason; Reflexive property
ΔPQM ≅ ΔPRM: Reason; Side Side Side (SSS) rule for triangle congruency
∠MPQ ≅ ∠MPR: Corresponding parts of congruent triangles are congruent CPCTC
∠PQR ≅∠PRQ: CPCTC
Answer: C
Step-by-step explanation:A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.
These fractions are not equal. This is not proportional.
x 2 3 4 5
y 7 9 11 13
These fractions are not equal. This is not proportional.
x 3 7.5 15 20
y 1 2.5 4 6
These fractions are not equal. This is not proportional.
x 3 6 8 10
y 12 15 18 20 HOPE IT HELPS:P
<h2>SO C</h2>
Answer - D.
you basically find the equation of the line first and eliminate the wrong answers...
Strategy: before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,
First you have to find the gradient (m) of the line.
you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2
replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others
Hope you get it!
Well knowing that the terminal arm of the standard position angle is in quadrant 2, we can determine the reference angle, in quadrant 2, by simply taking the difference between 180 and whatever the angle is.
So ø reference = 180 - ø in standard position.
Regardless, the reference angle is in quadrant 2, we need to then label the sides of the reference triangle based on the opposite and hypotenuse.
Solve for adjacent side using Pythagoras theorem.
A^2 = C^2 - B^2
A^2 = 3^2 - 2^2
A^2 = 9 - 4
A^2 =5
A = sq root of 5.
Then write the cos ratio using the new side.
Cos ø =✔️5/3. Place a negative in front of cos ø as cos is negative in second quadrant.
4, 16, 64, 256. The powers are 4 to the first. Four to the second, four to the third and four to the fourth power.