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andrew11 [14]
3 years ago
7

Which number sentence correctly models this algorithm for 75÷2.5​

Mathematics
1 answer:
natita [175]3 years ago
7 0

you need to add a photo or a problem in order to answer your question !

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I need help please.
4vir4ik [10]

Answer:

Hi! The correct answer is D. 0.0140

Step-by-step explanation:

<em>Convert</em> t<em>he</em> fraction part to a decimal then add the results to the whole number part.<em> </em>

8 0
3 years ago
If you are going to use the ASA postulate to prove these triangles congruent what additional information do you need?
Ugo [173]

Answer:

∠C and ∠R

Step-by-step explanation:

The ASA postulate represents angle / side / angle

where the included side is the side between the vertices of the two angles.

∠H and ∠I and the sides HC and IR are the AS

The required angles would be ∠C and ∠R for ASA

4 0
3 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
What is 56÷34×y and add 12
11Alexandr11 [23.1K]
Hey there! :)

PARENTHESES
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION

First is dividing

56 ÷ 34 = 56/34

56/34 = 28/17

56 ÷ 2 = 28
34 ÷ 2 = 17

Then multiply by y

28/17 × y = 28/17·y = 28y/17 or 28/17y

At last, you add 12

28y/17 + 12 = 28y/17 + 12

Your answer is: 28y/17 + 12

Hope this helps :)



7 0
3 years ago
Albert constructed a square box to hold jewelry. The
Stella [2.4K]
Each side is 23.5 meters
5 0
3 years ago
Read 2 more answers
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