Answer:
3/8
Step-by-step explanation:
this is because there are 8 students in all and only three of them are boys
Answer:
no real solution is the answer
If you have to list your extraneous solutions somewhere, that would be x=0.
Step-by-step explanation:
Cool thing here is the radical, the thing with the square root, is already isolate.
So we need to square both sides as a first step. (Whenever you raise both sides to even power, you must definitely check your solutions as some might not actually be solutions to the original equation)
So upon squaring both sides I get:
x^4+16=(x^2-4)^2
Now I will write (x^2-4)^2 as (x^2-4)(x^2-4) and foil it! This gives me:
x^4+16=x^4-8x^2+16
Subtract x^4 and 16 on both sides:
0=-8x^2
Divide both sides by -8
0=x^2
Therefore x=0.
0 isn't actually a solution though because when you plug it in you get 4=-4 which is not true.
When you multiply exponential expressions that have the same base, you simply add the exponents. This is true for both numbers and variables. When you include other numbers in the multiplication, you simply factor and break the expression into several multiplications.
2^5 * 2^x= 2^(5 + X)
