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3 years ago

PLZ HURRY Thank you and have a nice day

Mathematics

2 answers:

irga5000 [103]3 years ago

5 0

Answer:

multiply lol

Step-by-step explanation:

frez [133]3 years ago

5 0

Hi yes have a nice day

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Does someone know the answers to this if not can someone do it

77julia77 [94]

Answer:

in the pic below!!

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

4 years ago

5) A bowl has 20 marbles in it, 4 red, 5 blue, 8, green, and 3 yellow. What is the probability of picking yellow? a. 3/20 b. 4/2

matrenka [14]

Answer:

A. 3/20

Step-by-step explanation:

since there are 3 marbles, and 20 total marbles, you have a 3/20 chance of picking yellow

3 0

2 years ago

Read 2 more answers

The ratio of the areas of two similar

dezoksy [38]

Answer: 6 cm

Step-by-step explanation:

Given: The ratio of the areas of two similar parallelograms is 4:9.

To find : The height of the bigger one if the smaller is of height 4 cm.

Let h be the height of the bigger one.

Since the areas of similar figures are proportional to the square of their corresponding sides.

Then, $\dfrac{4^2}{h^2}=\dfrac{4}{9}$

$\dfrac{16}{h^2}=\dfrac{4}{9}\\\\\Rightarrow\ h^2=\dfrac{9}{4}\times16\\\\\Rightarrow\ h^2=36\\\\\Rightarow\ h= 6\ cm\ \ \ \ \text{[ height cannot be negative.]}$

Hence, the height of bigger parallelogram = 6 cm

3 0

3 years ago

The length of a rectangle is 4 cm less than twice its width. The perimeter of the

myrzilka [38]

Step-by-step explanation:

Let width be x

according to question

length = 2x-4

perimeter = 58

now,

perimeter = 2(length + width)

58 = 2(x+2x-4)

58 = 6x-8

6x = 66

x = 11

putting value of x in length

2x-4

= 2 X 11 -5

= 18

hence the dimensions of the rectangle is 18 and 11

4 0

3 years ago