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Lena [83]
3 years ago
14

A group of 10 people is choosing a chairperson and vice-chairperson. They put all 10 people's names into a hat. The first name d

rawn becomes chair. The second name drawn becomes vice-chair. How many possible combinations of chair and vice-chair are there?
Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Answer: 100

Step-by-step explanation:

10 people

2 chairs 1 chair 1 vice chair

10*10=100 different combinations

likoan [24]3 years ago
3 0

Answer:

45

Step-by-step explanation:

_{10} C_{2} = (10!) ÷(8!) (10-8)!

(10 × 9)÷2 = 45

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Find the sum of the first 20 terms of the arithmetic sequence 4, 10, 16, 22....
hammer [34]

n = 20

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a = 4

L = a + (n - 1)*d

L = 4 + (20 - 1)*6

L = 4 + 19*6

L = 118

Sum = (a + L)*n/2

Sum = (4 + 118) * 20/2

Sum = 122 * 10

Sum = 1220

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4 years ago
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mariarad [96]

Step-by-step explanation:

Let the required number be n

\therefore \:  \frac{90}{100}  \times n = x \\  \\ \therefore \:  \frac{9}{10}   \\  \\  \therefore \:n = \frac{10}{9} x \\  \\  \therefore 100\% \: of\:n = \frac{10}{9} x \times 100\% \\  \\  = \frac{10}{9} x \times \frac{100}{100}  \\  \\  =  \frac{10}{9} x  \\

NOTE: A number is always 100% in itself.

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Ede4ka [16]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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