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3 years ago

6

Harriet needs to ship a small vase. The box she will use has a volume of 216 inches. If the side lengths are all the same what i

s the length of each side of the box?

1 answer:

Pani-rosa [81]3 years ago

7 0

Volume of the box:
V = a ³ ( a - side length )
a ³ = 216 in³
a = ∛216
a = 6 in
Answer:
The length of each side of the box is 6 inches.

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A rectangular swimming pool measures 7.5 m by 4.5 m. It is completely surrounded by a fence parallel to each edge of the pool an

Illusion [34]

The total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

<h3>What is rectangle?</h3>

It is defined as the two-dimensional geometry in which the angle between the adjacent sides are 90 degree. It is a type of quadrilateral.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that:

A rectangular swimming pool measures 7.5 m by 4.5 m.

It is completely surrounded by a fence parallel to each edge of the pool and at a distance of 3 m from each edge of the pool.

The total length of the fence = 2(7.5+3×2 + 4.5+3×2)

The total length of the fence = 2(7.5+6 + 4.5+6)

The total length of the fence = 2(24)

The total length of the fence = 48 m

Thus, the total length of the fence is 48 m if the rectangular swimming pool measures 7.5 m by 4.5 m.

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2 years ago

4(1/2x + 2) = 6

Goshia [24]

x=2. -5/6 have a great rest of your day

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3 years ago

Suppose that in one metropolitan area, 25% of all home- owners are insured against earthquake damage. Four home-owners are to be

emmasim [6.3K]

Answer:

Step-by-step explanation:

Given that,

25% home owners are insecure of earthquake problem

If we select 4 home owners at random

let X denote the number among the four who have earthquake insurance

Let find the probability distribution of X

Let S- denotes a home owner who has insurance

Let F denotes a home owner who does not have insurance.

Then, P(S) =25% = 0.25

P(F) = 1 — P(S) = 1 —0.25

P(F) = 0.75

The possible outcomes of X is

X(0) = If no person has insurance

X(1) = If only 1 person has insurance

X(2) = If only 2 persons has insurance

X(3) = If only 3 persons has insurance

X(4) = If only 4 persons has insurance.

The cardinality of the sample space is n(C) = 2ⁿ = 2⁴ => 16

So, the sample space is given as

{FFFF, FFFS, FFSF, FFSS, FSFF, FSFS, FSSF, FSSS, SFFF, SFFS, SFSF, SFSS, SSFF, SSFS, SSSF, SSSS}

For X=0, the possible is {FFFF} i.e. no insurance, the one without insurance.

P(X) = 0.25×0.25×0.25×0.25

P(X) = 0.25⁴

P(X) = 0.00390625

For X=1, the possible outcome are

FFFS, FFSF, FSFF, SFFF

P(X=1) = 0.25³•0.75 + 0.25³•0.75 + 0.25³•0.75 + 0.25³•0.75

P(X=1) = 0.046875

For X=2 the possible outcomes are

FFSS, FSFS, FSSF, SFFS, SFSF, SSFF,

P(X=2)=0.25²•0.75²+0.25²•0.75²+ 0.25²•0.75²+ 0.25²•0.75²+ 0.25²•0.75²+ 0.25²•0.75²

P(X=2) = 0.2109375

For X=3 the possible outcomes are

FSSS, SFSS, SSFS, SSSF

P(X=3) = 0.25•0.75³+0.25•0.75³+ 0.25•0.75³+0.25•0.75³

P(X=3) = 0.421875

X=4 the possible outcomes are

SSSS

P(X=4) = 0.75×0.75×0.75×0.75

P(X=4) = 0.31640625.

Or

Using normal distribution

P(X=k) = ⁿCk • 0.25^k • 0.75^(4-k)

So,

P(X=0) = 4C0 • 0.25^0 • 0.75^4

P(X=0) = 0.31640625

P(X=1) = 4C1 • 0.25^1 • 0.75^3

P(X=1) = 0.421875

P(X=2) = 4C2 • 0.25^2 • 0.75^2

P(X=2) = 0.2109375

P(X=3) = 4C3 • 0.25^3 • 0.75^1

P(X=3) = 0.046875

P(X=4) = 4C4 • 0.25^4 • 0.75^0

P(X=4) = 0.00390625.

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3 years ago

Algebraic expression for 8+6q+q

irina1246 [14]

All you can do to this expression is simplify.

You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:

$6q + 1q = 7q$

Therefore your end result is:

$8 +7q$

3 0

4 years ago

(i) 809, 708, 607, _____, _ class 4<br>__class 4

schepotkina [342]

Answer:

809, 708, 607, 506, 405, 304, 203, 102, 1, -100

Step-by-step explanation:

809, 708, 607, _____, _______

First term = 809

Second term = 708

Third term = 607

Difference between first term and second term = 809 - 708

= 101

Difference between second term and third term = 708 - 607

= 101

Therefore, the common difference is 101

Fourth term = 607 - 101

= 506

Fifth term = 506 - 101

= 405

Sixth term = 405 - 101

= 304

Seventh term = 304 - 101

= 203

Eighth term = 203 - 101

= 102

Ninth term = 102 - 101

= 1

Tenth term = 1 - 101

= - 100

809, 708, 607, 506, 405, 304, 203, 102, 1, -100

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3 years ago