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3 years ago

Question for JAFAR2007

Mathematics

2 answers:

Burka [1]3 years ago

4 0

Answer:

Solution given:

x²+x-20=0

x²+5x-4x-20=0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

either.

x=-5

x=4

luda_lava [24]3 years ago

3 0

Step-by-step explanation:

x² + x -20 =0

or, x²+(5-4)x -20

or,x ²+5x -4x -20=0

or,x(x +5)-4(x+5)=0

or,(x+5)(x-4)=o

either,

x+5=0. x-4=0

or,x=0-5. or,x= 0+4

or,x=-5. or, x=4

hope it is helpful to you ☺️

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Answer:

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3 years ago

A building in a city has a rectangular base. The length of the base measures 75 ft less than three times the width. The

MariettaO [177]

The dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

<h3>What are the dimensions of the rectangle base?</h3>

The perimeter of rectangle is expressed as;

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Given the data in the question;

Let x represent the width of the rectangular base.

Width w = x
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Plug these values into the equation above.

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Therefore, the dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.

Learn more about rectangles here: brainly.com/question/17043956

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2 years ago

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Yuki888 [10]

For this case we must simplify the following expression:

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So, we have to:

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We factor the highest common denominator of each group:

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$\frac {4x ^ 2-32x + 48} {3x ^ 2-17x-6} = \frac {x-2} {3x + 1}$

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