28-(3c+4)=2(c+6)+c Solve for c

1 answer:

3 0

$Omiting\ brackets:\\28-(3c+4)=2(c+6)+c\\\\28-3c-4=2c+12+c\\\\-3c-2c-c=12-28+4\\\\-6c=12\ \ \ \ \ |:-6\\\\c=-2$

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