A 48 inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece

Question

Charra [1.4K]

3 years ago

14

A 48 inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece

is 3 times as long as the first piece

Mathematics

1 answer:

Y_Kistochka [10] · Answer 1 · 2022-03-07T09:31:02+03:00

Complete question :

A 48 inch board in to be cut into three pieces so that the second piece is twice as long as the first, and the third piece in 3 times as long as the first. If x represents the length of the first, find the lengths of all three

Answer:

Length of first piece = x = 8

Length of second = 2x = 8*2 = 16

Length of third = 3x = 8 * 3 = 24

Step-by-step explanation:

Let :

Length of first piece = x

Length of second = 2x

Length of third = 3x

The total lengtb of board = 48 inches

Hence,

First + second + third = 48

x + 2x + 3x = 48

6x = 48

x = 48 / 6

x = 8

Length of first piece = x = 8

Length of second = 2x = 8*2 = 16

Length of third = 3x = 8 * 3 = 24