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dybincka [34]
3 years ago
11

If you shift the quadratic parent function f(x))=x^2right 12 units what is the equation o the new function

Mathematics
1 answer:
Bond [772]3 years ago
5 0

hmm

the question doesn't look clear

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HELP ASAP!<br> PLEASE, I'LL MARK YOU AS BRAINLIST IF YOU GET ANSWER RIGHT!
Anna007 [38]
A, it’s A. As both parties have negatives.
8 0
3 years ago
What is the slope of a line perpendicular to the line y = 2x + 5? Type a numerical answer in the space provided. Do not type spa
Rama09 [41]

Answer:

  -1/2

Step-by-step explanation:

The slope of the given line is the coefficient of x, which is 2.

The slope of the perpendicular line is the negative reciprocal of that:

  -1/2

4 0
3 years ago
Graph the solution of the inequality on a number line. x − (5 − 3x) ≤ 2x − 1
egoroff_w [7]

Answer:

  • x ≤  2

Step-by-step explanation:

  • x − (5 − 3x) ≤ 2x − 1
  • x - 5 + 3x  ≤  2x - 1
  • 4x - 5 ≤  2x - 1
  • 4x - 2x ≤  5 - 1
  • 2x ≤  4
  • x ≤  2 or x ∈ (- oo, 2]

The graph includes all point to the left from point 2, same point included

4 0
3 years ago
Read 2 more answers
Ben and Ella are filling goodie bags for a party. Each goodie bag needs an eraser, a bubble wand, and a few candy bar bites. Ben
maxonik [38]

Answer:

Ben

Step-by-step explanation:

25 goodies = 20 minutes

27 goodies = 24 minutes

Let's use ratio, divide both of them by their minute

25/20 = 20/20

27/24 = 24/24

1.25 goodies = 1 minute

1.12 goodies = 1 minute

1.25 is bigger than 1.12.

7 0
3 years ago
Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
3 years ago
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