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3 years ago

Program to calculate series 10+9+8+...+n" in java with output

Computers and Technology

1 answer:

avanturin [10]3 years ago

5 0

Answer:

import java.util.Scanner;

class Main {

public static int calcSeries(int n) {

int sum = 0;

for(int i=10; i>=n; i--) {

sum += i;

}

return sum;

}

public static void main(String[] args) {

Scanner reader = new Scanner(System.in);

int n = 0;

do {

System.out.print("Enter n: ");

n = reader.nextInt();

if (n >= 10) {

System.out.println("Please enter a value lower than 10.");

}

} while (n >= 10);

reader.close();

System.out.printf("sum: %d\n", calcSeries(n));

}

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3 years ago

What is the output of the following program?

Contact [7]

The question is poorly formatted:

#include <stdio.h>

int main() {

int arr [5] = {1, 2, 3, 4, 5};

arr [1] = 0;

arr [3] = 0;

for (int i = 0;i < 5; i+=1)

printf("%d", arr[i]);

return 0;

}

Answer:

The output is 10305

Explanation:

I'll start my explanation from the third line

This line declares and initializes integer array arr of 5 integer values

int arr [5] = {1, 2, 3, 4, 5};

This line sets the value of arr[1] to 0

arr [1] = 0;

At this point, the content of the array becomes arr [5] = {1, 0, 3, 4, 5};

This line sets the value of arr[3] to 0

arr [3] = 0;

At this point, the content of the array becomes arr [5] = {1, 0, 3, 0, 5};

The next two lines is an iteration;

The first line of the iteration iterates the value of i order from 0 to 4

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3 years ago

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3 years ago

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emmainna [20.7K]

Answer:

In Python:

entry = input("Sentence: ")

while True:

if entry.count(",") == 0:

print("Error: No comma in string")

entry = input("Sentence: ")

elif entry.count(",") > 1:

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The following loop is repeated until the user enters a valid entry

while True:

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