Answer:
a) 255
b) 61602
c)
d)
Explanation:
You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>
For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:
a. F F
position 1 0
Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

Finally, you'll add your results:
240+15=255
FF=255
b. F 0 A 2
position 3 2 1 0

F0A2=61602
c. F 1 0 0
position 3 2 1 0

0F100=61696
d. 1 0 0
position 2 1 0

100=256
I hope you find this information useful! Good luck!
Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
Answer:
import java.util.Scanner;
import java.lang.*;
class Main
{
public static void main(String args[])
{
int n;
//For capturing the value of n
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the value of n:");
//The entered value is stored in the var n
n = scanner.nextInt();
int k=1;
printnum(n,k);
}
public static void printnum(int n,int k)
{
if(n%2==0)
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
else
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
n--;
if(n<=1)
{
System.exit(0);
}
else
{
printnum(n,k+1);
}
}
}
Explanation:
The program is self explanatory.
Answer: Memory hierarchy is the hierarchy that is created on the basis of the response time of different memories. The performance obtained by the memory helps in creating a computer storage space in distinguished form. The factors considered for the creating of the hierarchy structure are usually response time, storage capacity, complexity etc.
Usage of different kind of memories take place due to different kind of requirements from the system which cannot be fulfilled using one memory device.The requirement is based on saving time, decreasing complexity , improving performance etc.Example of requirements can be like some functions and files do not require much space , some might require quick accessing,etc.
Thus hierarchy of any particular system is in the form of fast to slow order from registers,cache memory, Random access memory(RAM) and secondary memory.
Important printer characteristics include resolution, speed, color, and cache memory.