1.Most aquatic animals have fins or paddles that help them swim
2. Skin is usually slippery and soft
Answer:
It is possible to compare the expression of homologous genes in the brain of <em>D. melanoganster</em> and humans, because the expression levels of conserved genes may be associated with the evolution of cognitive features such as complex learning and memory.
Explanation:
Model organisms can be used to understand the patterns and processes that affect human evolution. <em>Drosophila melanogaster </em>is a model organism that has been used to study expression patterns of conserved genes in the course of evolution. This model organism has also been used to develop genetic mutant lines in order to examine the role of genes evolutionarily conserved in animals, including those involved in neurocognitive development.
In genetic research, an experiment as the above described is framed in a research field named 'Behavioral Genetics', which is a discipline that studies how evolutionarily conserved gene networks may be associated with neurocognitive tasks during brain evolution.
When people don't know how to drive the boat correctly and they loose control.
Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
True, DNA is DNA, it matters not wether or not it belongs to a plant, you could mix a carrot with a pig (not sure why you would, but you can)
