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Ivan

3 years ago

absmiddle" class="latex-formula">

Mathematics

2 answers:

Tema [17]3 years ago

5 0

X1= -4
x2= 5/2 or 2.5

juin [17]3 years ago

3 0

21 the answer is 212131313133747583297475757472884756272847e

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yequals(9 x Superscript 4 Baseline minus 4 x squared plus 6 )Superscript 4 To find StartFraction dy Over dx EndFraction , write

damaskus [11]

Answer:

Step-by-step explanation:

Given the function

y = (9x⁴ — 4x² + 6)⁴

We need to find the derivative of y with respect to x i.e. dy/dx.

So let u = 9x⁴—4x² + 6

Then y = u²,

Then, y is a function of u, y=f(u)

Also, u is a function of x, u = g(x)

In this case,

u = g(x) = 9x⁴—4x² + 6

So let differentiate this function y(x).

This is a function of a function

Then, we need to find u'(x)

u (x) = 9x⁴—4x² + 6

Then, u'(x) = 36x³ — 8x

Also we need to find y'(u)

Then, y = u²

y'(u) = 2u

Using function of a function formula

dy / dx = dy/du × du/dx

y'(x) = y'(u) × u'(x)

y'(x) = 2u × 36x³ — 8x

y'(x) = 2u(36x³ — 8x)

Since, u = 9x⁴—4x² + 6

Therefore,

y'(t) = 2(9x⁴—4x² + 6)(36x³ — 8x)

So,

dy/dx = 2(9x⁴—4x² + 6)(36x³ — 8x)

dy/dx = (18x⁴—8x² + 12)(36x³ — 8x)

5 0

3 years ago

Can someone plz help with math?!

Flura [38]

Answer:

1. <em>L = 3D +59</em>

2. 158 miles

Step-by-step explanation:

For the second part:

Since each day 3 miles of the road is being added, we can simply multiply the number 33 by 3, getting 99. If the road started with 59 miles, we need to add 59 to 99, getting 158 miles.

5 0

3 years ago

What is 9365+643-9433+7.99999 repeating

nika2105 [10]

It is 780.99999 sorry if i'm incorrect

5 0

4 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Consider the following equation. cos x = x3 (a) Prove that the equation has at least one real root. f(x) = cos x − x3 is continu

skelet666 [1.2K]

Answer:

b. 0.86, 0.87

Step-by-step explanation:

a. Find attached solution to a

4 0

3 years ago