Consider the following equation. cos x = x3 (a) Prove that the equation has at least one real root. f(x) = cos x − x3 is continu
ous on the interval [0, 1], f(0) = 0, and f(1) = cos 1 − 1 ≈ −0.46 0. Since 0 −0.46, there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos x − x3 = , or cos x = x3, in the interval (0, 1). (b) Use your calculator to find an interval of length 0.01 that contains a root.
1 answer:
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Answer:
Option C) The two quantities are equal.
Step-by-step explanation:
We are given the following in the question:
n is a negative integer and p is a positive integer.
Quantity A: The product of the integers from n to p
Quantity B: 0
Quantity A is the product of integers from n to p. Since all the integers from n to p will include zero between them, thus the product of all the integers from n to p will be zero.
The product takes place in the following manner:
Thus, both the quantities are equal.
Option C) The two quantities are equal.
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Answer:
C. 2x^2 -8x +3 +1/(x +4)
Step-by-step explanation:
Synthetic division is useful for finding the quotient. Or, you can use polynomial long division. The result is the same, but synthetic division requires less writing.
